How much does a silicate brick weigh?

The first silicate bricks appeared at the end of the 19th century. Germany is considered the birthplace of building material, although experiments on the production of similar bricks were carried out in many other countries.

Inexpensive high-quality building material consists mainly of quartz sand (about 90%), lime (slightly less than 10%) and a small amount of additives. Manufacturing method - autoclave. The original components are mixed, pressed and subjected to treatment with water vapor at a temperature of 200 degrees.

There are several types of sand-lime bricks. By design features, they are divided into:

• full-bodied;
• hollow, voids are both through and non-through (voidness can be up to 45%).

By destination:

• private (used for the construction of masonry);
• facing (is a finishing building material).

In appearance:

• unpainted;
• color.

By dimensions:

• double;
• one and a half;
• single.

The length and width of all bricks are the same. The parameters are strictly observed, as they are established by a special state regulation (GOST 530-2012). The first parameter (length) corresponds to 250 mm, the second (width) is 120 mm. Only the height of the silicate is subject to changes.

By size, you can determine the type of bricks. So, single has parameters 250x120x65 mm, one and a half - 250x120x88 mm, and double - 250x120x138 mm.

The color of the bricks is obtained by adding pigments during the production process. Over time, the color practically does not change, since the dyes are resistant to environmental influences. Colored bricks (they can be pink, yellow, red or blue) are used for facing work.

Distinguish between volumetric and specific gravity of bricks. Volumetric weight depends on the design features of the building material. Of great importance for this value are voids in the body of the stone, as well as its density. To determine the volumetric weight, the mass of the brick in kilograms should be divided by its volume in cubic meters.

Lining products with voids have the lowest volumetric weight. The considered value for such bricks is only 1200 kg for a double one and 1400 kg for a one-and-a-half product per cubic meter. From 1300 to 1640 kg per cube is accounted for by working blocks with voids.

Single solid bricks have the highest volumetric weight. A cube of building material weighs 1900 kg. A cube of one-and-a-half solid bricks accounts for 1700 kg. The volumetric weight is involved in calculating the load of the masonry on the foundation. The value is obtained by multiplying the specific gravity by the volume of the masonry.

The specific gravity is influenced by the quality of raw materials and porosity. To determine this value, the volume of all voids is subtracted from the total volume of the brick. Then the mass of the stone must be divided by the "clean" volume. The normal specific gravity is in the range from 2000 to 2400 kilograms per cubic meter. A decrease in the indicator will indicate a low quality of the material.

Silicate bricks are often used in the construction of residential buildings and technical structures. The capital structure will not last long if the technical requirements are not followed.The main condition for the durability of any building is the correct ratio of the selected base (foundation) and the load on it. Therefore, even at the design stage, the weight of the silicate brick should be determined.

Due to the variety of types of silicate bricks, you should decide on the desired type of masonry, the presence or absence of a facing layer. Walls are most often built of white one-and-a-half bricks. Unlike single, one and a half, significantly speeds up the construction process. The mass of a standard one and a half specimen without holes corresponds on average to 4.9-5 kg. With increasing humidity, the weight increases.

When performing calculations of a building structure, it is not enough to know how much 1 piece weighs. single, double or one and a half bricks. As a rule, another indicator is used - cube. It is important to determine the weight of the masonry in cubic meters.

When calculating the required value, do not forget to bring the results to one unit of measurement. So, the dimensions of a standard brick are given in millimeters, and the volume, as a rule, is calculated in cubic meters. To perform calculations, the length, width and height of one block must be converted to meters.

Delivery of building materials to the customer is carried out in packs installed on a pallet. The number of bricks on a small wooden pallet is always the same. For example, there are 280 single blocks in a pack. Considering that the weight of 1 piece. is 3.7 kg, it turns out that in one package 1036 kg.

By simple calculations, you can determine the number of different types of bricks in one cube, as well as their weight.

The weight of a brick can be obtained by multiplying its volume by its specific gravity. Specific gravity is a reference value established by the standard. True, this rule applies only to full-bodied specimens. Hollows and grooved surfaces reduce the weight of the bricks. The more voids, the less the building material weighs.

Consider an example of calculating the weight of one standard solid silicate brick for each of its types. The initial data are overall dimensions and density. The second indicator remains unchanged for all options. It varies between 1.8-1.95 g / cm3. For calculations, we will take the minimum density of 1.8 g per cubic centimeter.

Calculations require determining the volume of one piece of brick. In this case, the overall dimensions should be taken into account in centimeters:

• 25x12x6.5 = 1950 cm3 (for single);
• 25x12x8.8 = 2640 cm3 (for one and a half);
• 25x12x13.8 = 4140 cm3 (for double).

The weight is obtained by multiplying the obtained volumes by the density and converting the result to kilograms by dividing by 1000:

• 1950 x 1.8 / 1000 = 3.510 kg;
• 2640 x 1.8 / 1000 = 4.751 kg;
• 4140 x 1.8 / 1000 = 7.453 kg.

For hollow bricks, void volumes should be taken into account. The easiest way to determine the parameters of through cylindrical voids. Due to the fact that the slots are made strictly perpendicular to the largest plane of the bricks, the length of the cylinder is known. It is equal to the block height:

• 6.5 cm for a single;
• 8.8 cm for one and a half;
• 13.8 cm for the double.

From the school curriculum, the formula for the area of ​​a circle is known: πr2. Number π = 3.14. It remains to measure the diameter of the hole.

Suppose the diameter of the through hole is 40 mm, then the radius is half as much - 20 mm. We accept the number of holes equal to 3 pcs. In this case, the volume of the brick will decrease by the sum of the volumes of the voids. The volume of each of the voids is 6.5 (cylinder length) x 3.14 (dimensionless constant π) x (2x2) (hole radius squared) = 81.64 cm3. The result is tripled by the number of holes. 81.64 x 3 = 244.92 cm3.

The volume of a single stone in cubic centimeters: 25 x 12 x 6.5 = 1950 cm3. After removing the volume of voids, we obtain the initial volume of the brick for determining the weight: 1950 - 244.92 = 1705.08 cm3. The specific density of hollow blocks is in the range of 1.1-1.5 g / cm3. Multiplying the density by the "net" volume will give the weight of the brick.For example, we take the maximum density, we get the weight: 1.5 x 1705.08 = 2557.62 g, or 2.55 kg.

All you need to know about silicate brick is in the video below.